What are the solutions to the equation y^2-5y=-6 ?

The solutions to the equation y^2-5y=-6 are y=3,y=2

Find the zeros of y^2-5y=-6

The zeros of y^2-5y=-6 are y=3,y=2

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y^{2} - 5 y = - 6

y = 3, y = 2

Solution steps

y^{2} - 5 y = - 6

Move

6

to the left side

y^{2} - 5 y + 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

y_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, y_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

y = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

y = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

y = 3, y = 2

t, h = \frac{1}{2} g t^{2} + v t

(2 x + 10) x = 100

7 (x - 4)^{2} - 2 = 54

3 b^{2} - 10 b - 8 = 0

x, k x^{2} + 36 x + k = 0

What are the solutions to the equation y^2-5y=-6 ?
The solutions to the equation y^2-5y=-6 are y=3,y=2
Find the zeros of y^2-5y=-6
The zeros of y^2-5y=-6 are y=3,y=2