What are the solutions to the equation -3x^2+72=-60 ?

The solutions to the equation -3x^2+72=-60 are x=2sqrt(11),x=-2sqrt(11)

Find the zeros of -3x^2+72=-60

The zeros of -3x^2+72=-60 are x=2sqrt(11),x=-2sqrt(11)

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- 3 x^{2} + 72 = - 60

x = 211, x = - 211

Decimal Notation

x = 6.63324 \dots, x = - 6.63324 \dots

Solution steps

- 3 x^{2} + 72 = - 60

Move

72

to the right side

- 3 x^{2} = - 132

Divide both sides by

- 3

x^{2} = 44

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 44, x = - 44

44 = 211

- 44 = - 211

x = 211, x = - 211

0.01 x^{2} - 2 x + 4 = 0

x, x^{2} + y^{2} = a

\frac{( x + 6 ) ^{2}}{2} = 8

- 6 x^{2} + 48 x - 72 = 0

n^{2} - 10 n + 22 = - 2

What are the solutions to the equation -3x^2+72=-60 ?
The solutions to the equation -3x^2+72=-60 are x=2sqrt(11),x=-2sqrt(11)
Find the zeros of -3x^2+72=-60
The zeros of -3x^2+72=-60 are x=2sqrt(11),x=-2sqrt(11)