What are the solutions to the equation 0=t^2-3t ?

The solutions to the equation 0=t^2-3t are t=3,t=0

Find the zeros of 0=t^2-3t

The zeros of 0=t^2-3t are t=3,t=0

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0 = t^{2} - 3 t

t = 3, t = 0

Solution steps

0 = t^{2} - 3 t

Switch sides

t^{2} - 3 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

t_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, t_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

t = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

t = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 3, t = 0

y, x^{3} + x^{2} y + 4 y^{2} = 6

v^{2} + 11 v + 24 = 0

y, x^{2} y^{2} + 3 y = 4 x

2 x^{2} + \frac{3}{7} x - 8 = 0

(x - 4)^{2} - 121 = 0

What are the solutions to the equation 0=t^2-3t ?
The solutions to the equation 0=t^2-3t are t=3,t=0
Find the zeros of 0=t^2-3t
The zeros of 0=t^2-3t are t=3,t=0