What are the solutions to the equation (x-4)^2-121=0 ?

The solutions to the equation (x-4)^2-121=0 are x=15,x=-7

Find the zeros of (x-4)^2-121=0

The zeros of (x-4)^2-121=0 are x=15,x=-7

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(x - 4)^{2} - 121 = 0

x = 15, x = - 7

Solution steps

(x - 4)^{2} - 121 = 0

Move

121

to the right side

(x - 4)^{2} = 121

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 121 : x = 15

Solve

x - 4 = - 121 : x = - 7

The solutions to the quadratic equation are:

x = 15, x = - 7

x^{2} = 12 x

x, z = 4 - x^{2} - y^{2}

y, x^{2} + x y^{2} + y^{2} = 1

m^{2} + m + 6 = 0

x^{2} + 20 x = 69

What are the solutions to the equation (x-4)^2-121=0 ?
The solutions to the equation (x-4)^2-121=0 are x=15,x=-7
Find the zeros of (x-4)^2-121=0
The zeros of (x-4)^2-121=0 are x=15,x=-7