What are the solutions to the equation m^2+m+6=0 ?

The solutions to the equation m^2+m+6=0 are m=-1/2+i(sqrt(23))/2 ,m=-1/2-i(sqrt(23))/2

Find the zeros of m^2+m+6=0

The zeros of m^2+m+6=0 are m=-1/2+i(sqrt(23))/2 ,m=-1/2-i(sqrt(23))/2

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m^{2} + m + 6 = 0

m = - \frac{1}{2} + i \frac{23}{2}, m = - \frac{1}{2} - i \frac{23}{2}

Solution steps

m^{2} + m + 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 6 : 23 i

m_{1, 2} = \frac{- 1 \pm 23 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 1 + 23 i}{2 \cdot 1}, m_{2} = \frac{- 1 - 23 i}{2 \cdot 1}

m = \frac{- 1 + 23 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{23}{2}

m = \frac{- 1 - 23 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{23}{2}

The solutions to the quadratic equation are:

m = - \frac{1}{2} + i \frac{23}{2}, m = - \frac{1}{2} - i \frac{23}{2}

x^{2} + 20 x = 69

- 16 x^{2} + 1362 = 0

x^{2} + 15 x + 62 = 6

x^{2} - 9 (x - 1)^{2} = 0

x^{2} - 2 x + 7 = 4

What are the solutions to the equation m^2+m+6=0 ?
The solutions to the equation m^2+m+6=0 are m=-1/2+i(sqrt(23))/2 ,m=-1/2-i(sqrt(23))/2
Find the zeros of m^2+m+6=0
The zeros of m^2+m+6=0 are m=-1/2+i(sqrt(23))/2 ,m=-1/2-i(sqrt(23))/2