What are the solutions to the equation x^2-9(x-1)^2=0 ?

The solutions to the equation x^2-9(x-1)^2=0 are x= 3/4 ,x= 3/2

Find the zeros of x^2-9(x-1)^2=0

The zeros of x^2-9(x-1)^2=0 are x= 3/4 ,x= 3/2

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x^{2} - 9 (x - 1)^{2} = 0

x = \frac{3}{4}, x = \frac{3}{2}

Decimal Notation

x = 0.75, x = 1.5

Solution steps

x^{2} - 9 (x - 1)^{2} = 0

Expand

x^{2} - 9 (x - 1)^{2} : - 8 x^{2} + 18 x - 9

- 8 x^{2} + 18 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 ( - 8 ) ( - 9 )}{2 ( - 8 )}

1 8^{2} - 4 (- 8) (- 9) = 6

x_{1, 2} = \frac{- 18 \pm 6}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 18 + 6}{2 ( - 8 )}, x_{2} = \frac{- 18 - 6}{2 ( - 8 )}

x = \frac{- 18 + 6}{2 ( - 8 )} : \frac{3}{4}

x = \frac{- 18 - 6}{2 ( - 8 )} : \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = \frac{3}{2}

x^{2} - 2 x + 7 = 4

1 - 0.5 x + 0.3 x^{2} = 0

6 x^{2} - 18 x - 24 = 62

12 m^{2} - 4 m - 17 = 0

b^{2} - 4 b - 3 = 0

What are the solutions to the equation x^2-9(x-1)^2=0 ?
The solutions to the equation x^2-9(x-1)^2=0 are x= 3/4 ,x= 3/2
Find the zeros of x^2-9(x-1)^2=0
The zeros of x^2-9(x-1)^2=0 are x= 3/4 ,x= 3/2