What are the solutions to the equation roots x^2-6x+34 ?

The solutions to the equation roots x^2-6x+34 are x=3+5i,x=3-5i

Find the zeros of roots x^2-6x+34

The zeros of roots x^2-6x+34 are x=3+5i,x=3-5i

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roots

x^{2} - 6 x + 34

x = 3 + 5 i, x = 3 - 5 i

Solution steps

x^{2} - 6 x + 34

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 6 x + 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 34}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 34 : 10 i

x_{1, 2} = \frac{- ( - 6 ) \pm 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 10 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 10 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 10 i}{2 \cdot 1} : 3 + 5 i

x = \frac{- ( - 6 ) - 10 i}{2 \cdot 1} : 3 - 5 i

The solutions to the quadratic equation are:

x = 3 + 5 i, x = 3 - 5 i

x^{2} - 3 x + 1 = 0

P, \frac{P V}{T} = \frac{P ^{2} V ^{2}}{T ^{2}}

- 2 \cdot x^{2} + 11 \cdot x + c = 0

(2 x + 10) (x - 4) = 0

x^{2} - 10 x + 25 = 0

What are the solutions to the equation roots x^2-6x+34 ?
The solutions to the equation roots x^2-6x+34 are x=3+5i,x=3-5i
Find the zeros of roots x^2-6x+34
The zeros of roots x^2-6x+34 are x=3+5i,x=3-5i