What are the solutions to the equation 4(x^2-9)-8=-19 ?

The solutions to the equation 4(x^2-9)-8=-19 are x= 5/2 ,x=-5/2

Find the zeros of 4(x^2-9)-8=-19

The zeros of 4(x^2-9)-8=-19 are x= 5/2 ,x=-5/2

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4 (x^{2} - 9) - 8 = - 19

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 2.5, x = - 2.5

Solution steps

4 (x^{2} - 9) - 8 = - 19

Move

8

to the right side

4 (x^{2} - 9) = - 11

Divide both sides by

4

x^{2} - 9 = - \frac{11}{4}

Move

9

to the right side

x^{2} = \frac{25}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{4}, x = - \frac{25}{4}

\frac{25}{4} = \frac{5}{2}

- \frac{25}{4} = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

b, \frac{b ^{2}}{2} - \frac{t ^{2}}{8} = 1

y, x^{2} - 3 x y + 2 y^{2} = 0

x, 80 = - 42 x - x^{2}

(2 y - 1)^{2} - 4 = 6 y - 1

- 33 p = - p^{2}

What are the solutions to the equation 4(x^2-9)-8=-19 ?
The solutions to the equation 4(x^2-9)-8=-19 are x= 5/2 ,x=-5/2
Find the zeros of 4(x^2-9)-8=-19
The zeros of 4(x^2-9)-8=-19 are x= 5/2 ,x=-5/2