What are the solutions to the equation -33p=-p^2 ?

The solutions to the equation -33p=-p^2 are p=0,p=33

Find the zeros of -33p=-p^2

The zeros of -33p=-p^2 are p=0,p=33

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- 33 p = - p^{2}

p = 0, p = 33

Solution steps

- 33 p = - p^{2}

Switch sides

- p^{2} = - 33 p

Move

33 p

to the left side

- p^{2} + 33 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 33 \pm 3 3 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

3 3^{2} - 4 (- 1) \cdot 0 = 33

p_{1, 2} = \frac{- 33 \pm 33}{2 ( - 1 )}

Separate the solutions

p_{1} = \frac{- 33 + 33}{2 ( - 1 )}, p_{2} = \frac{- 33 - 33}{2 ( - 1 )}

p = \frac{- 33 + 33}{2 ( - 1 )} : 0

p = \frac{- 33 - 33}{2 ( - 1 )} : 33

The solutions to the quadratic equation are:

p = 0, p = 33

2 x^{2} - 12 x - 9 = 0

4 q^{2} + q + 1 = - 3 q

0 = 2 x^{2} - 8 x

10 n^{2} + 15 n - 25 = 6 n^{2}

x, z = 2 x^{2} - 4 y^{2}

What are the solutions to the equation -33p=-p^2 ?
The solutions to the equation -33p=-p^2 are p=0,p=33
Find the zeros of -33p=-p^2
The zeros of -33p=-p^2 are p=0,p=33