What are the solutions to the equation 2x^2-12x-9=0 ?

The solutions to the equation 2x^2-12x-9=0 are x=(3(2+sqrt(6)))/2 ,x=(3(2-sqrt(6)))/2

Find the zeros of 2x^2-12x-9=0

The zeros of 2x^2-12x-9=0 are x=(3(2+sqrt(6)))/2 ,x=(3(2-sqrt(6)))/2

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2 x^{2} - 12 x - 9 = 0

x = \frac{3 ( 2 + 6 )}{2}, x = \frac{3 ( 2 - 6 )}{2}

Decimal Notation

x = 6.67423 \dots, x = - 0.67423 \dots

Solution steps

2 x^{2} - 12 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 (- 9) = 66

x_{1, 2} = \frac{- ( - 12 ) \pm 6 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 6}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 6 6}{2 \cdot 2}

x = \frac{- ( - 12 ) + 6 6}{2 \cdot 2} : \frac{3 ( 2 + 6 )}{2}

x = \frac{- ( - 12 ) - 6 6}{2 \cdot 2} : \frac{3 ( 2 - 6 )}{2}

The solutions to the quadratic equation are:

x = \frac{3 ( 2 + 6 )}{2}, x = \frac{3 ( 2 - 6 )}{2}

4 q^{2} + q + 1 = - 3 q

0 = 2 x^{2} - 8 x

10 n^{2} + 15 n - 25 = 6 n^{2}

x, z = 2 x^{2} - 4 y^{2}

\times (- 16) y^{2} = 0

What are the solutions to the equation 2x^2-12x-9=0 ?
The solutions to the equation 2x^2-12x-9=0 are x=(3(2+sqrt(6)))/2 ,x=(3(2-sqrt(6)))/2
Find the zeros of 2x^2-12x-9=0
The zeros of 2x^2-12x-9=0 are x=(3(2+sqrt(6)))/2 ,x=(3(2-sqrt(6)))/2