What are the solutions to the equation 25/36 =(x-3)^2 ?

The solutions to the equation 25/36 =(x-3)^2 are x= 23/6 ,x= 13/6

Find the zeros of 25/36 =(x-3)^2

The zeros of 25/36 =(x-3)^2 are x= 23/6 ,x= 13/6

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\frac{25}{36} = (x - 3)^{2}

x = \frac{23}{6}, x = \frac{13}{6}

Decimal Notation

x = 3.83333 \dots, x = 2.16666 \dots

Solution steps

\frac{25}{36} = (x - 3)^{2}

Switch sides

(x - 3)^{2} = \frac{25}{36}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = \frac{25}{36} : x = \frac{23}{6}

Solve

x - 3 = - \frac{25}{36} : x = \frac{13}{6}

The solutions to the quadratic equation are:

x = \frac{23}{6}, x = \frac{13}{6}

x^{2} - 4 x + 12 = 0

\frac{u ^{2} - 1}{2} = \frac{u}{3}

2 x^{2} - 8 x + 5 = 0

- 12 + 12 x - 3 x^{2} = 0

x^{2} + 5 x - \frac{7}{4} = 0

What are the solutions to the equation 25/36 =(x-3)^2 ?
The solutions to the equation 25/36 =(x-3)^2 are x= 23/6 ,x= 13/6
Find the zeros of 25/36 =(x-3)^2
The zeros of 25/36 =(x-3)^2 are x= 23/6 ,x= 13/6