What are the solutions to the equation x^2+5x-7/4 =0 ?

The solutions to the equation x^2+5x-7/4 =0 are x=(-5+4sqrt(2))/2 ,x=-(5+4sqrt(2))/2

Find the zeros of x^2+5x-7/4 =0

The zeros of x^2+5x-7/4 =0 are x=(-5+4sqrt(2))/2 ,x=-(5+4sqrt(2))/2

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x^{2} + 5 x - \frac{7}{4} = 0

x = \frac{- 5 + 4 2}{2}, x = - \frac{5 + 4 2}{2}

Decimal Notation

x = 0.32842 \dots, x = - 5.32842 \dots

Solution steps

x^{2} + 5 x - \frac{7}{4} = 0

Multiply both sides by

4

4 x^{2} + 20 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 (- 7) = 162

x_{1, 2} = \frac{- 20 \pm 16 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 20 + 16 2}{2 \cdot 4}, x_{2} = \frac{- 20 - 16 2}{2 \cdot 4}

x = \frac{- 20 + 16 2}{2 \cdot 4} : \frac{- 5 + 4 2}{2}

x = \frac{- 20 - 16 2}{2 \cdot 4} : - \frac{5 + 4 2}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 4 2}{2}, x = - \frac{5 + 4 2}{2}

x^{2} - 11 x + 22 = - 2

4 x^{2} + 56 x + 144 = 0

x^{2} + 6 x + 3 = - x (x - 1)

(\frac{16}{9}) x^{2} = 64

x, 3 x^{2} - 2 + 2 s in x = 0

What are the solutions to the equation x^2+5x-7/4 =0 ?
The solutions to the equation x^2+5x-7/4 =0 are x=(-5+4sqrt(2))/2 ,x=-(5+4sqrt(2))/2
Find the zeros of x^2+5x-7/4 =0
The zeros of x^2+5x-7/4 =0 are x=(-5+4sqrt(2))/2 ,x=-(5+4sqrt(2))/2