What are the solutions to the equation roots 4x^2-4x+1=0 ?

The solutions to the equation roots 4x^2-4x+1=0 are x= 1/2

Find the zeros of roots 4x^2-4x+1=0

The zeros of roots 4x^2-4x+1=0 are x= 1/2

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roots

4 x^{2} - 4 x + 1 = 0

x = \frac{1}{2}

Solution steps

4 x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

(12 x + 18) (1.6 - 0.2 x) = 0

7 m + m^{2} + 10 = 0

3 x^{2} + \frac{9}{2} x - 4 = 5 x + \frac{3}{4}

y, x + x y + 2 y^{2} = 6

2 x^{2} - 20 x + 58

What are the solutions to the equation roots 4x^2-4x+1=0 ?
The solutions to the equation roots 4x^2-4x+1=0 are x= 1/2
Find the zeros of roots 4x^2-4x+1=0
The zeros of roots 4x^2-4x+1=0 are x= 1/2