What are the solutions to the equation -3/4 x^2+9/4 x+3=3 ?

The solutions to the equation -3/4 x^2+9/4 x+3=3 are x=0,x=3

Find the zeros of -3/4 x^2+9/4 x+3=3

The zeros of -3/4 x^2+9/4 x+3=3 are x=0,x=3

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- \frac{3}{4} x^{2} + \frac{9}{4} x + 3 = 3

x = 0, x = 3

Solution steps

- \frac{3}{4} x^{2} + \frac{9}{4} x + 3 = 3

Multiply both sides by

4

- 3 x^{2} + 9 x + 12 = 12

Move

12

to the left side

- 3 x^{2} + 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

9^{2} - 4 (- 3) \cdot 0 = 9

x_{1, 2} = \frac{- 9 \pm 9}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 9 + 9}{2 ( - 3 )}, x_{2} = \frac{- 9 - 9}{2 ( - 3 )}

x = \frac{- 9 + 9}{2 ( - 3 )} : 0

x = \frac{- 9 - 9}{2 ( - 3 )} : 3

The solutions to the quadratic equation are:

x = 0, x = 3

(x - 9)^{2} = - 16

x^{2} - \frac{4}{5} x + \frac{16}{25} = 0

20 b^{2} - 125 = 0

x^{2} - 1 = - 8

p^{2} - p - 30 = 0

What are the solutions to the equation -3/4 x^2+9/4 x+3=3 ?
The solutions to the equation -3/4 x^2+9/4 x+3=3 are x=0,x=3
Find the zeros of -3/4 x^2+9/4 x+3=3
The zeros of -3/4 x^2+9/4 x+3=3 are x=0,x=3