What are the solutions to the equation x=2(x-1)^2+8 ?

The solutions to the equation x=2(x-1)^2+8 are x= 5/4+i(sqrt(55))/4 ,x= 5/4-i(sqrt(55))/4

Find the zeros of x=2(x-1)^2+8

The zeros of x=2(x-1)^2+8 are x= 5/4+i(sqrt(55))/4 ,x= 5/4-i(sqrt(55))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x = 2 (x - 1)^{2} + 8

x = \frac{5}{4} + i \frac{55}{4}, x = \frac{5}{4} - i \frac{55}{4}

Solution steps

x = 2 (x - 1)^{2} + 8

Expand

2 (x - 1)^{2} + 8 : 2 x^{2} - 4 x + 10

x = 2 x^{2} - 4 x + 10

Switch sides

2 x^{2} - 4 x + 10 = x

Move

x

to the left side

2 x^{2} - 5 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 10}{2 \cdot 2}

Simplify

(- 5)^{2} - 4 \cdot 2 \cdot 10 : 55 i

x_{1, 2} = \frac{- ( - 5 ) \pm 55 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 55 i}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 55 i}{2 \cdot 2}

x = \frac{- ( - 5 ) + 55 i}{2 \cdot 2} : \frac{5}{4} + i \frac{55}{4}

x = \frac{- ( - 5 ) - 55 i}{2 \cdot 2} : \frac{5}{4} - i \frac{55}{4}

The solutions to the quadratic equation are:

x = \frac{5}{4} + i \frac{55}{4}, x = \frac{5}{4} - i \frac{55}{4}

2 x^{2} + 6 = 8 x

25 = 65 t - 5 t^{2}

6 b^{2} - 13 b + 3 = - 3

b^{2} - 4 b - 621 = 0

- a^{2} = 0

What are the solutions to the equation x=2(x-1)^2+8 ?
The solutions to the equation x=2(x-1)^2+8 are x= 5/4+i(sqrt(55))/4 ,x= 5/4-i(sqrt(55))/4
Find the zeros of x=2(x-1)^2+8
The zeros of x=2(x-1)^2+8 are x= 5/4+i(sqrt(55))/4 ,x= 5/4-i(sqrt(55))/4