What are the solutions to the equation b^2-4b-621=0 ?

The solutions to the equation b^2-4b-621=0 are b=27,b=-23

Find the zeros of b^2-4b-621=0

The zeros of b^2-4b-621=0 are b=27,b=-23

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b^{2} - 4 b - 621 = 0

b = 27, b = - 23

Solution steps

b^{2} - 4 b - 621 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 621 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 621) = 50

b_{1, 2} = \frac{- ( - 4 ) \pm 50}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- ( - 4 ) + 50}{2 \cdot 1}, b_{2} = \frac{- ( - 4 ) - 50}{2 \cdot 1}

b = \frac{- ( - 4 ) + 50}{2 \cdot 1} : 27

b = \frac{- ( - 4 ) - 50}{2 \cdot 1} : - 23

The solutions to the quadratic equation are:

b = 27, b = - 23

- a^{2} = 0

1.5 x^{2} - 0.5 x = 0

9 x^{2} - 8 x = 19

r^{2} - 6 r - 16 = - 5

0 = 3 x^{2} - 16 x + 24

What are the solutions to the equation b^2-4b-621=0 ?
The solutions to the equation b^2-4b-621=0 are b=27,b=-23
Find the zeros of b^2-4b-621=0
The zeros of b^2-4b-621=0 are b=27,b=-23