What are the solutions to the equation 9x^2-8x=19 ?

The solutions to the equation 9x^2-8x=19 are x=(4+sqrt(187))/9 ,x=(4-sqrt(187))/9

Find the zeros of 9x^2-8x=19

The zeros of 9x^2-8x=19 are x=(4+sqrt(187))/9 ,x=(4-sqrt(187))/9

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9 x^{2} - 8 x = 19

x = \frac{4 + 187}{9}, x = \frac{4 - 187}{9}

Decimal Notation

x = 1.96386 \dots, x = - 1.07497 \dots

Solution steps

9 x^{2} - 8 x = 19

Move

19

to the left side

9 x^{2} - 8 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 9 ( - 19 )}{2 \cdot 9}

(- 8)^{2} - 4 \cdot 9 (- 19) = 2187

x_{1, 2} = \frac{- ( - 8 ) \pm 2 187}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 187}{2 \cdot 9}, x_{2} = \frac{- ( - 8 ) - 2 187}{2 \cdot 9}

x = \frac{- ( - 8 ) + 2 187}{2 \cdot 9} : \frac{4 + 187}{9}

x = \frac{- ( - 8 ) - 2 187}{2 \cdot 9} : \frac{4 - 187}{9}

The solutions to the quadratic equation are:

x = \frac{4 + 187}{9}, x = \frac{4 - 187}{9}

r^{2} - 6 r - 16 = - 5

0 = 3 x^{2} - 16 x + 24

4.9 x^{2} - 6 x - 20 = 0

x^{2} + 2 x - 35 = 0

y, χ y^{2} z^{3} = 2

What are the solutions to the equation 9x^2-8x=19 ?
The solutions to the equation 9x^2-8x=19 are x=(4+sqrt(187))/9 ,x=(4-sqrt(187))/9
Find the zeros of 9x^2-8x=19
The zeros of 9x^2-8x=19 are x=(4+sqrt(187))/9 ,x=(4-sqrt(187))/9