What are the solutions to the equation 6x^2-5x-5=0 ?

The solutions to the equation 6x^2-5x-5=0 are x=(5+sqrt(145))/(12),x=(5-sqrt(145))/(12)

Find the zeros of 6x^2-5x-5=0

The zeros of 6x^2-5x-5=0 are x=(5+sqrt(145))/(12),x=(5-sqrt(145))/(12)

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6 x^{2} - 5 x - 5 = 0

x = \frac{5 + 145}{12}, x = \frac{5 - 145}{12}

Decimal Notation

x = 1.42013 \dots, x = - 0.58679 \dots

Solution steps

6 x^{2} - 5 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 (- 5) = 145

x_{1, 2} = \frac{- ( - 5 ) \pm 145}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 145}{2 \cdot 6}, x_{2} = \frac{- ( - 5 ) - 145}{2 \cdot 6}

x = \frac{- ( - 5 ) + 145}{2 \cdot 6} : \frac{5 + 145}{12}

x = \frac{- ( - 5 ) - 145}{2 \cdot 6} : \frac{5 - 145}{12}

The solutions to the quadratic equation are:

x = \frac{5 + 145}{12}, x = \frac{5 - 145}{12}

12 x^{2} + 16 x = 0

3 x^{2} + x + 4 = - 9 x + 1

x, 61 x^{2} - 20 x - 32 = 0

12 x^{2} - 17 x - 6 = 7 x^{2} + 6

y, x + y^{2} = 2

What are the solutions to the equation 6x^2-5x-5=0 ?
The solutions to the equation 6x^2-5x-5=0 are x=(5+sqrt(145))/(12),x=(5-sqrt(145))/(12)
Find the zeros of 6x^2-5x-5=0
The zeros of 6x^2-5x-5=0 are x=(5+sqrt(145))/(12),x=(5-sqrt(145))/(12)