What are the solutions to the equation -5x^2+9x-3=0 ?

The solutions to the equation -5x^2+9x-3=0 are x=(9-sqrt(21))/(10),x=(9+sqrt(21))/(10)

Find the zeros of -5x^2+9x-3=0

The zeros of -5x^2+9x-3=0 are x=(9-sqrt(21))/(10),x=(9+sqrt(21))/(10)

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- 5 x^{2} + 9 x - 3 = 0

x = \frac{9 - 21}{10}, x = \frac{9 + 21}{10}

Decimal Notation

x = 0.44174 \dots, x = 1.35825 \dots

Solution steps

- 5 x^{2} + 9 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 5 ) ( - 3 )}{2 ( - 5 )}

9^{2} - 4 (- 5) (- 3) = 21

x_{1, 2} = \frac{- 9 \pm 21}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 9 + 21}{2 ( - 5 )}, x_{2} = \frac{- 9 - 21}{2 ( - 5 )}

x = \frac{- 9 + 21}{2 ( - 5 )} : \frac{9 - 21}{10}

x = \frac{- 9 - 21}{2 ( - 5 )} : \frac{9 + 21}{10}

The solutions to the quadratic equation are:

x = \frac{9 - 21}{10}, x = \frac{9 + 21}{10}

x^{2} = 14 x - 40

39 = 113 t - 16 t^{2}

x^{2} + 7 x + 3 = 3

- 4 t^{2} + 32 t = - 132

x^{2} + (4 x + 16)^{2} = (4 x + 17)^{2}

What are the solutions to the equation -5x^2+9x-3=0 ?
The solutions to the equation -5x^2+9x-3=0 are x=(9-sqrt(21))/(10),x=(9+sqrt(21))/(10)
Find the zeros of -5x^2+9x-3=0
The zeros of -5x^2+9x-3=0 are x=(9-sqrt(21))/(10),x=(9+sqrt(21))/(10)