What are the solutions to the equation 2x^2-6x+7=10.5 ?

The solutions to the equation 2x^2-6x+7=10.5 are x= 7/2 ,x=-1/2

Find the zeros of 2x^2-6x+7=10.5

The zeros of 2x^2-6x+7=10.5 are x= 7/2 ,x=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 6 x + 7 = 10.5

x = \frac{7}{2}, x = - \frac{1}{2}

Decimal Notation

x = 3.5, x = - 0.5

Solution steps

2 x^{2} - 6 x + 7 = 10.5

Multiply both sides by

10

20 x^{2} - 60 x + 70 = 105

Move

105

to the left side

20 x^{2} - 60 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 20 ( - 35 )}{2 \cdot 20}

(- 60)^{2} - 4 \cdot 20 (- 35) = 80

x_{1, 2} = \frac{- ( - 60 ) \pm 80}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 60 ) + 80}{2 \cdot 20}, x_{2} = \frac{- ( - 60 ) - 80}{2 \cdot 20}

x = \frac{- ( - 60 ) + 80}{2 \cdot 20} : \frac{7}{2}

x = \frac{- ( - 60 ) - 80}{2 \cdot 20} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - \frac{1}{2}

9 x^{2} + 5 x = 12 + 6 x + 3 x^{2}

2 x^{2} - x - 1

16 n^{2} = 25

y, (x + 2)^{2} + (y - 4)^{2} = - 12

240 = 128 t - 16 t^{2}

What are the solutions to the equation 2x^2-6x+7=10.5 ?
The solutions to the equation 2x^2-6x+7=10.5 are x= 7/2 ,x=-1/2
Find the zeros of 2x^2-6x+7=10.5
The zeros of 2x^2-6x+7=10.5 are x= 7/2 ,x=-1/2