What are the solutions to the equation 450=3(x-1)(x-6) ?

The solutions to the equation 450=3(x-1)(x-6) are x=16,x=-9

Find the zeros of 450=3(x-1)(x-6)

The zeros of 450=3(x-1)(x-6) are x=16,x=-9

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450 = 3 (x - 1) (x - 6)

x = 16, x = - 9

Solution steps

450 = 3 (x - 1) (x - 6)

Expand

3 (x - 1) (x - 6) : 3 x^{2} - 21 x + 18

450 = 3 x^{2} - 21 x + 18

Switch sides

3 x^{2} - 21 x + 18 = 450

Move

450

to the left side

3 x^{2} - 21 x - 432 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 3 ( - 432 )}{2 \cdot 3}

(- 21)^{2} - 4 \cdot 3 (- 432) = 75

x_{1, 2} = \frac{- ( - 21 ) \pm 75}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 21 ) + 75}{2 \cdot 3}, x_{2} = \frac{- ( - 21 ) - 75}{2 \cdot 3}

x = \frac{- ( - 21 ) + 75}{2 \cdot 3} : 16

x = \frac{- ( - 21 ) - 75}{2 \cdot 3} : - 9

The solutions to the quadratic equation are:

x = 16, x = - 9

t^{2} - 5 t - 5 = - 2 t

- 2 x^{2} - 2 x - 4 = 0

2 x^{2} + x - 1

8 x^{2} - 33 x + 4 = 0

x - x^{2} = \frac{1}{6}

What are the solutions to the equation 450=3(x-1)(x-6) ?
The solutions to the equation 450=3(x-1)(x-6) are x=16,x=-9
Find the zeros of 450=3(x-1)(x-6)
The zeros of 450=3(x-1)(x-6) are x=16,x=-9