What are the solutions to the equation -2x^2-2x-4=0 ?

The solutions to the equation -2x^2-2x-4=0 are x=-1/2-i(sqrt(7))/2 ,x=-1/2+i(sqrt(7))/2

Find the zeros of -2x^2-2x-4=0

The zeros of -2x^2-2x-4=0 are x=-1/2-i(sqrt(7))/2 ,x=-1/2+i(sqrt(7))/2

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- 2 x^{2} - 2 x - 4 = 0

x = - \frac{1}{2} - i \frac{7}{2}, x = - \frac{1}{2} + i \frac{7}{2}

Solution steps

- 2 x^{2} - 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 2 ) ( - 4 )}{2 ( - 2 )}

Simplify

(- 2)^{2} - 4 (- 2) (- 4) : 27 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 7 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 7 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 2 ) - 2 7 i}{2 ( - 2 )}

x = \frac{- ( - 2 ) + 2 7 i}{2 ( - 2 )} : - \frac{1}{2} - i \frac{7}{2}

x = \frac{- ( - 2 ) - 2 7 i}{2 ( - 2 )} : - \frac{1}{2} + i \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} - i \frac{7}{2}, x = - \frac{1}{2} + i \frac{7}{2}

2 x^{2} + x - 1

8 x^{2} - 33 x + 4 = 0

x - x^{2} = \frac{1}{6}

6 x^{2} = 7 x + 2

4 x^{2} + 11 x - 45 = 0

What are the solutions to the equation -2x^2-2x-4=0 ?
The solutions to the equation -2x^2-2x-4=0 are x=-1/2-i(sqrt(7))/2 ,x=-1/2+i(sqrt(7))/2
Find the zeros of -2x^2-2x-4=0
The zeros of -2x^2-2x-4=0 are x=-1/2-i(sqrt(7))/2 ,x=-1/2+i(sqrt(7))/2