What are the solutions to the equation x^2-8x+31=0 ?

The solutions to the equation x^2-8x+31=0 are x=4+sqrt(15)i,x=4-sqrt(15)i

Find the zeros of x^2-8x+31=0

The zeros of x^2-8x+31=0 are x=4+sqrt(15)i,x=4-sqrt(15)i

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x^{2} - 8 x + 31 = 0

x = 4 + 15 i, x = 4 - 15 i

Solution steps

x^{2} - 8 x + 31 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 31}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 31 : 215 i

x_{1, 2} = \frac{- ( - 8 ) \pm 2 15 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 15 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 15 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 15 i}{2 \cdot 1} : 4 + 15 i

x = \frac{- ( - 8 ) - 2 15 i}{2 \cdot 1} : 4 - 15 i

The solutions to the quadratic equation are:

x = 4 + 15 i, x = 4 - 15 i

x^{2} - x + 5 = 5

9 x^{2} + 6 x - 2 = 0

x (x + 21) = 100

- 7 (x + 5) = x^{2} + (5 - a) x - 5 a

y, (3 x - y)^{2} + (x - 5)^{2} = 0

What are the solutions to the equation x^2-8x+31=0 ?
The solutions to the equation x^2-8x+31=0 are x=4+sqrt(15)i,x=4-sqrt(15)i
Find the zeros of x^2-8x+31=0
The zeros of x^2-8x+31=0 are x=4+sqrt(15)i,x=4-sqrt(15)i