What are the solutions to the equation -10s^2+17s=3 ?

The solutions to the equation -10s^2+17s=3 are s= 1/5 ,s= 3/2

Find the zeros of -10s^2+17s=3

The zeros of -10s^2+17s=3 are s= 1/5 ,s= 3/2

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- 10 s^{2} + 17 s = 3

s = \frac{1}{5}, s = \frac{3}{2}

Decimal Notation

s = 0.2, s = 1.5

Solution steps

- 10 s^{2} + 17 s = 3

Move

3

to the left side

- 10 s^{2} + 17 s - 3 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 ( - 10 ) ( - 3 )}{2 ( - 10 )}

1 7^{2} - 4 (- 10) (- 3) = 13

s_{1, 2} = \frac{- 17 \pm 13}{2 ( - 10 )}

Separate the solutions

s_{1} = \frac{- 17 + 13}{2 ( - 10 )}, s_{2} = \frac{- 17 - 13}{2 ( - 10 )}

s = \frac{- 17 + 13}{2 ( - 10 )} : \frac{1}{5}

s = \frac{- 17 - 13}{2 ( - 10 )} : \frac{3}{2}

The solutions to the quadratic equation are:

s = \frac{1}{5}, s = \frac{3}{2}

x^{2} + 5 = 26.16

7 n^{2} - 49 n = 0

x^{2} - 2 x - 3 = x + 1

x^{2} + 3 x + 18 = - 2

x^{2} - 6 x + k

What are the solutions to the equation -10s^2+17s=3 ?
The solutions to the equation -10s^2+17s=3 are s= 1/5 ,s= 3/2
Find the zeros of -10s^2+17s=3
The zeros of -10s^2+17s=3 are s= 1/5 ,s= 3/2