What are the solutions to the equation completesquare x^2+12x+32=0 ?

The solutions to the equation completesquare x^2+12x+32=0 are x=-4,x=-8

Find the zeros of completesquare x^2+12x+32=0

The zeros of completesquare x^2+12x+32=0 are x=-4,x=-8

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x^{2} + 12 x + 32 = 0

x = - 4, x = - 8

Solution steps

x^{2} + 12 x + 32 = 0

Move

32

to the right side

x^{2} + 12 x = - 32

Rewrite in the form

(x + a)^{2} = b

(x + 6)^{2} = 4

For

the solutions are

f (x) = a, - a

Solve

x + 6 = 4 : x = - 4

Solve

x + 6 = - 4 : x = - 8

The solutions to the quadratic equation are:

x = - 4, x = - 8

x, 128 = 192 - x^{2}

x^{2} - 9 = - 8 x

x^{2} - 10 x + 49 = 4 x + 1

x^{2} + 7 x + 10

\frac{x}{2} - \frac{1}{5} = \frac{x ^{2}}{5}

What are the solutions to the equation completesquare x^2+12x+32=0 ?
The solutions to the equation completesquare x^2+12x+32=0 are x=-4,x=-8
Find the zeros of completesquare x^2+12x+32=0
The zeros of completesquare x^2+12x+32=0 are x=-4,x=-8