What are the solutions to the equation factor x^2-10x+49=4x+1 ?

The solutions to the equation factor x^2-10x+49=4x+1 are x=6,x=8

Find the zeros of factor x^2-10x+49=4x+1

The zeros of factor x^2-10x+49=4x+1 are x=6,x=8

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x^{2} - 10 x + 49 = 4 x + 1

x = 6, x = 8

Solution steps

x^{2} - 10 x + 49 = 4 x + 1

Move

1

to the left side

x^{2} - 10 x + 48 = 4 x

Move

4 x

to the left side

x^{2} - 14 x + 48 = 0

Factor

x^{2} - 14 x + 48 : (x - 6) (x - 8)

(x - 6) (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or x - 8 = 0

Solve

x - 6 = 0 : x = 6

Solve

x - 8 = 0 : x = 8

The solutions to the quadratic equation are:

x = 6, x = 8

x^{2} + 7 x + 10

\frac{x}{2} - \frac{1}{5} = \frac{x ^{2}}{5}

- \frac{3}{4} x^{2} + 12 x + 2 = 0

y = k^{2} - 8 k - 48

7 x^{2} + 5 x = 4 x^{2} - x

What are the solutions to the equation factor x^2-10x+49=4x+1 ?
The solutions to the equation factor x^2-10x+49=4x+1 are x=6,x=8
Find the zeros of factor x^2-10x+49=4x+1
The zeros of factor x^2-10x+49=4x+1 are x=6,x=8