What are the solutions to the equation -3/4 x^2+12x+2=0 ?

The solutions to the equation -3/4 x^2+12x+2=0 are x=-(2(5sqrt(6)-12))/3 ,x=(2(12+5sqrt(6)))/3

Find the zeros of -3/4 x^2+12x+2=0

The zeros of -3/4 x^2+12x+2=0 are x=-(2(5sqrt(6)-12))/3 ,x=(2(12+5sqrt(6)))/3

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- \frac{3}{4} x^{2} + 12 x + 2 = 0

x = - \frac{2 ( 5 6 - 12 )}{3}, x = \frac{2 ( 12 + 5 6 )}{3}

Decimal Notation

x = - 0.16496 \dots, x = 16.16496 \dots

Solution steps

- \frac{3}{4} x^{2} + 12 x + 2 = 0

Multiply both sides by

4

- 3 x^{2} + 48 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 ( - 3 ) \cdot 8}{2 ( - 3 )}

4 8^{2} - 4 (- 3) \cdot 8 = 206

x_{1, 2} = \frac{- 48 \pm 20 6}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 48 + 20 6}{2 ( - 3 )}, x_{2} = \frac{- 48 - 20 6}{2 ( - 3 )}

x = \frac{- 48 + 20 6}{2 ( - 3 )} : - \frac{2 ( 5 6 - 12 )}{3}

x = \frac{- 48 - 20 6}{2 ( - 3 )} : \frac{2 ( 12 + 5 6 )}{3}

The solutions to the quadratic equation are:

x = - \frac{2 ( 5 6 - 12 )}{3}, x = \frac{2 ( 12 + 5 6 )}{3}

y = k^{2} - 8 k - 48

7 x^{2} + 5 x = 4 x^{2} - x

4 (5 x + 8)^{2} - 23 = 13

\frac{1}{2} d^{2} + 4 d = - 12

y, 2 x^{2} - 3 x y + y^{2} - x + 2 y = 8

What are the solutions to the equation -3/4 x^2+12x+2=0 ?
The solutions to the equation -3/4 x^2+12x+2=0 are x=-(2(5sqrt(6)-12))/3 ,x=(2(12+5sqrt(6)))/3
Find the zeros of -3/4 x^2+12x+2=0
The zeros of -3/4 x^2+12x+2=0 are x=-(2(5sqrt(6)-12))/3 ,x=(2(12+5sqrt(6)))/3