What are the solutions to the equation (2/5)^2+x^2=1 ?

The solutions to the equation (2/5)^2+x^2=1 are x=(sqrt(21))/5 ,x=-(sqrt(21))/5

Find the zeros of (2/5)^2+x^2=1

The zeros of (2/5)^2+x^2=1 are x=(sqrt(21))/5 ,x=-(sqrt(21))/5

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(\frac{2}{5})^{2} + x^{2} = 1

x = \frac{21}{5}, x = - \frac{21}{5}

Decimal Notation

x = 0.91651 \dots, x = - 0.91651 \dots

Solution steps

(\frac{2}{5})^{2} + x^{2} = 1

Expand

(\frac{2}{5})^{2} + x^{2} : \frac{4}{25} + x^{2}

\frac{4}{25} + x^{2} = 1

Move

\frac{4}{25}

to the right side

x^{2} = 1 - \frac{4}{25}

Simplify

1 - \frac{4}{25} : \frac{21}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{21}{25}, x = - \frac{21}{25}

\frac{21}{25} = \frac{21}{5}

- \frac{21}{25} = - \frac{21}{5}

x = \frac{21}{5}, x = - \frac{21}{5}

x, x^{2} - 6 x + 8 = 0

12 x (x - 2) = 0

2 (1 - x^{2}) = 0

(2 x + 2) (x + 1) = 0

- 3 x^{2} - 3 x + 18 = 0

What are the solutions to the equation (2/5)^2+x^2=1 ?
The solutions to the equation (2/5)^2+x^2=1 are x=(sqrt(21))/5 ,x=-(sqrt(21))/5
Find the zeros of (2/5)^2+x^2=1
The zeros of (2/5)^2+x^2=1 are x=(sqrt(21))/5 ,x=-(sqrt(21))/5