What are the solutions to the equation -(x+4)^2=75 ?

The solutions to the equation -(x+4)^2=75 are x=5sqrt(3)i-4,x=-5sqrt(3)i-4

Find the zeros of -(x+4)^2=75

The zeros of -(x+4)^2=75 are x=5sqrt(3)i-4,x=-5sqrt(3)i-4

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- (x + 4)^{2} = 75

x = 53 i - 4, x = - 53 i - 4

Solution steps

- (x + 4)^{2} = 75

Divide both sides by

- 1

(x + 4)^{2} = - 75

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = - 75 : x = 53 i - 4

Solve

x + 4 = - - 75 : x = - 53 i - 4

The solutions to the quadratic equation are:

x = 53 i - 4, x = - 53 i - 4

8 s - 11 = (s - 4) (s - 2)

4 xx - 24 x + 36 = 0

3 a^{2} - 14 a + 12 = 0

x, x^{2} + 3 t x = c

\frac{1}{2} x^{2} + \frac{3}{8} x = 2

What are the solutions to the equation -(x+4)^2=75 ?
The solutions to the equation -(x+4)^2=75 are x=5sqrt(3)i-4,x=-5sqrt(3)i-4
Find the zeros of -(x+4)^2=75
The zeros of -(x+4)^2=75 are x=5sqrt(3)i-4,x=-5sqrt(3)i-4