What are the solutions to the equation 2x^2-x=120 ?

The solutions to the equation 2x^2-x=120 are x=8,x=-15/2

Find the zeros of 2x^2-x=120

The zeros of 2x^2-x=120 are x=8,x=-15/2

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2 x^{2} - x = 120

x = 8, x = - \frac{15}{2}

Decimal Notation

x = 8, x = - 7.5

Solution steps

2 x^{2} - x = 120

Move

120

to the left side

2 x^{2} - x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 120 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 120) = 31

x_{1, 2} = \frac{- ( - 1 ) \pm 31}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 31}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 31}{2 \cdot 2}

x = \frac{- ( - 1 ) + 31}{2 \cdot 2} : 8

x = \frac{- ( - 1 ) - 31}{2 \cdot 2} : - \frac{15}{2}

The solutions to the quadratic equation are:

x = 8, x = - \frac{15}{2}

x^{2} - 9 x - 20 = - 2 x - 2

(y + 14)^{2} + y^{2} - 25 = 0

y, x^{2} + y^{2} = - 5

y, x^{2} + y^{2} = - 4

a (x) = (x - 3) (4 x + 1) + 2 (3 - x) (x + 2)

What are the solutions to the equation 2x^2-x=120 ?
The solutions to the equation 2x^2-x=120 are x=8,x=-15/2
Find the zeros of 2x^2-x=120
The zeros of 2x^2-x=120 are x=8,x=-15/2