What are the solutions to the equation (2x+5)(-mx+9)=0 ?

The solutions to the equation (2x+5)(-mx+9)=0 are x=-5/2 ,x= 9/m ;\quad m\ne 0

Find the zeros of (2x+5)(-mx+9)=0

The zeros of (2x+5)(-mx+9)=0 are x=-5/2 ,x= 9/m ;\quad m\ne 0

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(2 x + 5) (- m x + 9) = 0

x = - \frac{5}{2}, x = \frac{9}{m}; m \neq = 0

Solution steps

(2 x + 5) (- m x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 5 = 0 or - m x + 9 = 0

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

Solve

- m x + 9 = 0 : x = \frac{9}{m}; m \neq = 0

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = \frac{9}{m}; m \neq = 0

x^{2} = 8 - 2 x

y, 3 x^{2} + 5 y^{2} - 6 x - 20 y = - 25

104 = 124 x - 14 x^{2}

2 c^{2} - 12 c + 7 = - 4 c

x^{2} - 7

What are the solutions to the equation (2x+5)(-mx+9)=0 ?
The solutions to the equation (2x+5)(-mx+9)=0 are x=-5/2 ,x= 9/m ;\quad m\ne 0
Find the zeros of (2x+5)(-mx+9)=0
The zeros of (2x+5)(-mx+9)=0 are x=-5/2 ,x= 9/m ;\quad m\ne 0