What are the solutions to the equation x^2=8-2x ?

The solutions to the equation x^2=8-2x are x=2,x=-4

Find the zeros of x^2=8-2x

The zeros of x^2=8-2x are x=2,x=-4

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x^{2} = 8 - 2 x

x = 2, x = - 4

Solution steps

x^{2} = 8 - 2 x

Move

2 x

to the left side

x^{2} + 2 x = 8

Move

8

to the left side

x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 8) = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 \cdot 1}, x_{2} = \frac{- 2 - 6}{2 \cdot 1}

x = \frac{- 2 + 6}{2 \cdot 1} : 2

x = \frac{- 2 - 6}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 2, x = - 4

y, 3 x^{2} + 5 y^{2} - 6 x - 20 y = - 25

104 = 124 x - 14 x^{2}

2 c^{2} - 12 c + 7 = - 4 c

x^{2} - 7

4 y^{2} + 3 y - 1 = 0

What are the solutions to the equation x^2=8-2x ?
The solutions to the equation x^2=8-2x are x=2,x=-4
Find the zeros of x^2=8-2x
The zeros of x^2=8-2x are x=2,x=-4