What are the solutions to the equation 4y^2+3y-1=0 ?

The solutions to the equation 4y^2+3y-1=0 are y= 1/4 ,y=-1

Find the zeros of 4y^2+3y-1=0

The zeros of 4y^2+3y-1=0 are y= 1/4 ,y=-1

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4 y^{2} + 3 y - 1 = 0

y = \frac{1}{4}, y = - 1

Decimal Notation

y = 0.25, y = - 1

Solution steps

4 y^{2} + 3 y - 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 1) = 5

y_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 4}

Separate the solutions

y_{1} = \frac{- 3 + 5}{2 \cdot 4}, y_{2} = \frac{- 3 - 5}{2 \cdot 4}

y = \frac{- 3 + 5}{2 \cdot 4} : \frac{1}{4}

y = \frac{- 3 - 5}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

y = \frac{1}{4}, y = - 1

x, 5 a x^{2} y - 5 x^{2} + 6 y^{3} = 100

(3 x + 1) (3 x - 1) = 5 x + 3

2 a^{2} - 5 a - 2 = - 3 a^{2}

m^{2} + 12 = 7 m

3 x^{2} = 6 x + 1

What are the solutions to the equation 4y^2+3y-1=0 ?
The solutions to the equation 4y^2+3y-1=0 are y= 1/4 ,y=-1
Find the zeros of 4y^2+3y-1=0
The zeros of 4y^2+3y-1=0 are y= 1/4 ,y=-1