What are the solutions to the equation m^2+12=7m ?

The solutions to the equation m^2+12=7m are m=4,m=3

Find the zeros of m^2+12=7m

The zeros of m^2+12=7m are m=4,m=3

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m^{2} + 12 = 7 m

m = 4, m = 3

Solution steps

m^{2} + 12 = 7 m

Move

7 m

to the left side

m^{2} + 12 - 7 m = 0

Write in the standard form

a x^{2} + b x + c = 0

m^{2} - 7 m + 12 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 12 = 1

m_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 1}, m_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 1}

m = \frac{- ( - 7 ) + 1}{2 \cdot 1} : 4

m = \frac{- ( - 7 ) - 1}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

m = 4, m = 3

3 x^{2} = 6 x + 1

5 x^{2} - 7 x = 2 x - 4

x^{2} - 2 = 1

x, x^{2} + 64 = 0

8 x^{2} - 8 = 0

What are the solutions to the equation m^2+12=7m ?
The solutions to the equation m^2+12=7m are m=4,m=3
Find the zeros of m^2+12=7m
The zeros of m^2+12=7m are m=4,m=3