What are the solutions to the equation factor 9x^2+60x+95=-5 ?

The solutions to the equation factor 9x^2+60x+95=-5 are x=-10/3

Find the zeros of factor 9x^2+60x+95=-5

The zeros of factor 9x^2+60x+95=-5 are x=-10/3

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9 x^{2} + 60 x + 95 = - 5

x = - \frac{10}{3}

Decimal Notation

x = - 3.33333 \dots

Solution steps

9 x^{2} + 60 x + 95 = - 5

Move

5

to the left side

9 x^{2} + 60 x + 100 = 0

Factor

9 x^{2} + 60 x + 100 : (3 x + 10)^{2}

(3 x + 10)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 10 = 0

Solve

3 x + 10 = 0 : x = - \frac{10}{3}

The solution to the quadratic equation is:

x = - \frac{10}{3}

- 6 x^{2} + 9 x - 7 = 0

2 x^{2} + 9 x - 56 = 0

3 = x^{2} - 4 x + 7

4 d^{2} - d - 7 = 2 d^{2}

- 4 x^{2} - 8 x + 1 = 0

What are the solutions to the equation factor 9x^2+60x+95=-5 ?
The solutions to the equation factor 9x^2+60x+95=-5 are x=-10/3
Find the zeros of factor 9x^2+60x+95=-5
The zeros of factor 9x^2+60x+95=-5 are x=-10/3