What are the solutions to the equation 49x^2=1 ?

The solutions to the equation 49x^2=1 are x= 1/7 ,x=-1/7

Find the zeros of 49x^2=1

The zeros of 49x^2=1 are x= 1/7 ,x=-1/7

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49 x^{2} = 1

x = \frac{1}{7}, x = - \frac{1}{7}

Decimal Notation

x = 0.14285 \dots, x = - 0.14285 \dots

Solution steps

49 x^{2} = 1

Divide both sides by

49

x^{2} = \frac{1}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{49}, x = - \frac{1}{49}

\frac{1}{49} = \frac{1}{7}

- \frac{1}{49} = - \frac{1}{7}

x = \frac{1}{7}, x = - \frac{1}{7}

16 x^{2} + 2 x - 3 = 0

x^{2} + x = 272

2 x^{2} + 34 x - 336 = 0

m^{2} - m = 1

0 = x^{2} - \frac{3}{2} x - \frac{70}{8}

What are the solutions to the equation 49x^2=1 ?
The solutions to the equation 49x^2=1 are x= 1/7 ,x=-1/7
Find the zeros of 49x^2=1
The zeros of 49x^2=1 are x= 1/7 ,x=-1/7