What are the solutions to the equation 2k^2+54=0 ?

The solutions to the equation 2k^2+54=0 are k=3sqrt(3)i,k=-3sqrt(3)i

Find the zeros of 2k^2+54=0

The zeros of 2k^2+54=0 are k=3sqrt(3)i,k=-3sqrt(3)i

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2 k^{2} + 54 = 0

k = 33 i, k = - 33 i

Solution steps

2 k^{2} + 54 = 0

Move

54

to the right side

2 k^{2} = - 54

Divide both sides by

2

k^{2} = - 27

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = - 27, k = - - 27

- 27 = 33 i

- - 27 = - 33 i

k = 33 i, k = - 33 i

3 r^{2} + 4 r + 10 = 0

8^{2} = x^{2} + 7^{2}

w^{2} - 22 w + 121 = 81

x^{2} - 7 = 6

2 (2 x - 4)^{2} - 41 = 29

What are the solutions to the equation 2k^2+54=0 ?
The solutions to the equation 2k^2+54=0 are k=3sqrt(3)i,k=-3sqrt(3)i
Find the zeros of 2k^2+54=0
The zeros of 2k^2+54=0 are k=3sqrt(3)i,k=-3sqrt(3)i