What are the solutions to the equation -12x-9=4x^2 ?

The solutions to the equation -12x-9=4x^2 are x=-3/2

Find the zeros of -12x-9=4x^2

The zeros of -12x-9=4x^2 are x=-3/2

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- 12 x - 9 = 4 x^{2}

x = - \frac{3}{2}

Decimal Notation

x = - 1.5

Solution steps

- 12 x - 9 = 4 x^{2}

Switch sides

4 x^{2} = - 12 x - 9

Move

9

to the left side

4 x^{2} + 9 = - 12 x

Move

12 x

to the left side

4 x^{2} + 9 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 \cdot 9 = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 4}

x = \frac{- 12}{2 \cdot 4}

\frac{- 12}{2 \cdot 4} = - \frac{3}{2}

x = - \frac{3}{2}

The solution to the quadratic equation is:

x = - \frac{3}{2}

x, z = 1 - x^{2} - y^{2}

- 8 x^{2} - 33 = - 9 x^{2} + 8 x

3 x^{2} - 2 = x^{2} + 6

y^{2} - 9 y + 1 = 2

3 x^{2} + 2 x - 1 = 2 x^{2} + 4 x + 2

What are the solutions to the equation -12x-9=4x^2 ?
The solutions to the equation -12x-9=4x^2 are x=-3/2
Find the zeros of -12x-9=4x^2
The zeros of -12x-9=4x^2 are x=-3/2