What are the solutions to the equation y^2-9y+1=2 ?

The solutions to the equation y^2-9y+1=2 are y=(9+sqrt(85))/2 ,y=(9-sqrt(85))/2

Find the zeros of y^2-9y+1=2

The zeros of y^2-9y+1=2 are y=(9+sqrt(85))/2 ,y=(9-sqrt(85))/2

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y^{2} - 9 y + 1 = 2

y = \frac{9 + 85}{2}, y = \frac{9 - 85}{2}

Decimal Notation

y = 9.10977 \dots, y = - 0.10977 \dots

Solution steps

y^{2} - 9 y + 1 = 2

Move

2

to the left side

y^{2} - 9 y - 1 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 1) = 85

y_{1, 2} = \frac{- ( - 9 ) \pm 85}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 9 ) + 85}{2 \cdot 1}, y_{2} = \frac{- ( - 9 ) - 85}{2 \cdot 1}

y = \frac{- ( - 9 ) + 85}{2 \cdot 1} : \frac{9 + 85}{2}

y = \frac{- ( - 9 ) - 85}{2 \cdot 1} : \frac{9 - 85}{2}

The solutions to the quadratic equation are:

y = \frac{9 + 85}{2}, y = \frac{9 - 85}{2}

3 x^{2} + 2 x - 1 = 2 x^{2} + 4 x + 2

j (x) = 2 x^{2} - 8 x + 10

0 = (x + 8) (6 x + 1)

y, x^{2} + 2 x y - y^{2} = 0

x^{2} + 22 x + 2

What are the solutions to the equation y^2-9y+1=2 ?
The solutions to the equation y^2-9y+1=2 are y=(9+sqrt(85))/2 ,y=(9-sqrt(85))/2
Find the zeros of y^2-9y+1=2
The zeros of y^2-9y+1=2 are y=(9+sqrt(85))/2 ,y=(9-sqrt(85))/2