What are the solutions to the equation 9x^2+18x-27=0 ?

The solutions to the equation 9x^2+18x-27=0 are x=1,x=-3

Find the zeros of 9x^2+18x-27=0

The zeros of 9x^2+18x-27=0 are x=1,x=-3

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9 x^{2} + 18 x - 27 = 0

x = 1, x = - 3

Solution steps

9 x^{2} + 18 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 9 ( - 27 )}{2 \cdot 9}

1 8^{2} - 4 \cdot 9 (- 27) = 36

x_{1, 2} = \frac{- 18 \pm 36}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 18 + 36}{2 \cdot 9}, x_{2} = \frac{- 18 - 36}{2 \cdot 9}

x = \frac{- 18 + 36}{2 \cdot 9} : 1

x = \frac{- 18 - 36}{2 \cdot 9} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

- 2 x^{2} - 2 x = 0

(x - 4)^{2} = 180

x^{2} - 3 x - 4

2 - (x^{2} - 3 x + 8) = (2 x - 3) (1 - x)

x, xx z - 250047 = 0

What are the solutions to the equation 9x^2+18x-27=0 ?
The solutions to the equation 9x^2+18x-27=0 are x=1,x=-3
Find the zeros of 9x^2+18x-27=0
The zeros of 9x^2+18x-27=0 are x=1,x=-3