What are the solutions to the equation 2W^2+7W-99=0 ?

The solutions to the equation 2W^2+7W-99=0 are W= 11/2 ,W=-9

Find the zeros of 2W^2+7W-99=0

The zeros of 2W^2+7W-99=0 are W= 11/2 ,W=-9

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2 W^{2} + 7 W - 99 = 0

W = \frac{11}{2}, W = - 9

Decimal Notation

W = 5.5, W = - 9

Solution steps

2 W^{2} + 7 W - 99 = 0

Solve with the quadratic formula

W_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 99 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 99) = 29

W_{1, 2} = \frac{- 7 \pm 29}{2 \cdot 2}

Separate the solutions

W_{1} = \frac{- 7 + 29}{2 \cdot 2}, W_{2} = \frac{- 7 - 29}{2 \cdot 2}

W = \frac{- 7 + 29}{2 \cdot 2} : \frac{11}{2}

W = \frac{- 7 - 29}{2 \cdot 2} : - 9

The solutions to the quadratic equation are:

W = \frac{11}{2}, W = - 9

4 x^{2} - 90 = 2 x

y, 4 x^{2} - 9 y^{2} - 16 x - 18 y + 7 = 0

x^{2} - 5 x - 10

a^{2} = 196

6 x^{2} - 13 x - 8 = 0

What are the solutions to the equation 2W^2+7W-99=0 ?
The solutions to the equation 2W^2+7W-99=0 are W= 11/2 ,W=-9
Find the zeros of 2W^2+7W-99=0
The zeros of 2W^2+7W-99=0 are W= 11/2 ,W=-9