What are the solutions to the equation roots x^2+5x+25 ?

The solutions to the equation roots x^2+5x+25 are x=-5/2+i(5sqrt(3))/2 ,x=-5/2-i(5sqrt(3))/2

Find the zeros of roots x^2+5x+25

The zeros of roots x^2+5x+25 are x=-5/2+i(5sqrt(3))/2 ,x=-5/2-i(5sqrt(3))/2

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roots

x^{2} + 5 x + 25

x = - \frac{5}{2} + i \frac{5 3}{2}, x = - \frac{5}{2} - i \frac{5 3}{2}

Solution steps

x^{2} + 5 x + 25

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 5 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

5^{2} - 4 \cdot 1 \cdot 25 : 53 i

x_{1, 2} = \frac{- 5 \pm 5 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 5 3 i}{2 \cdot 1}, x_{2} = \frac{- 5 - 5 3 i}{2 \cdot 1}

x = \frac{- 5 + 5 3 i}{2 \cdot 1} : - \frac{5}{2} + i \frac{5 3}{2}

x = \frac{- 5 - 5 3 i}{2 \cdot 1} : - \frac{5}{2} - i \frac{5 3}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2} + i \frac{5 3}{2}, x = - \frac{5}{2} - i \frac{5 3}{2}

4 (10 - 5 x)^{2} = 49

x^{2} - 2 x - 4

x, x^{2} + 2 y^{2} + z^{2} - 4 x + 4 y - 2 z + 3 = 0

180 + 6 q - 4 q^{2} = 2 q^{2}

24 x^{2} + 15 x = 0

What are the solutions to the equation roots x^2+5x+25 ?
The solutions to the equation roots x^2+5x+25 are x=-5/2+i(5sqrt(3))/2 ,x=-5/2-i(5sqrt(3))/2
Find the zeros of roots x^2+5x+25
The zeros of roots x^2+5x+25 are x=-5/2+i(5sqrt(3))/2 ,x=-5/2-i(5sqrt(3))/2