What are the solutions to the equation roots x^2-2x-4 ?

The solutions to the equation roots x^2-2x-4 are x=1+sqrt(5),x=1-sqrt(5)

Find the zeros of roots x^2-2x-4

The zeros of roots x^2-2x-4 are x=1+sqrt(5),x=1-sqrt(5)

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roots

x^{2} - 2 x - 4

x = 1 + 5, x = 1 - 5

Solution steps

x^{2} - 2 x - 4

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 4) = 25

x_{1, 2} = \frac{- ( - 2 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 5}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 5}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 5}{2 \cdot 1} : 1 + 5

x = \frac{- ( - 2 ) - 2 5}{2 \cdot 1} : 1 - 5

The solutions to the quadratic equation are:

x = 1 + 5, x = 1 - 5

x, x^{2} + 2 y^{2} + z^{2} - 4 x + 4 y - 2 z + 3 = 0

180 + 6 q - 4 q^{2} = 2 q^{2}

24 x^{2} + 15 x = 0

x^{2} + 11 x - 4 = 0

x^{2} + 11 x + 28 = 70

What are the solutions to the equation roots x^2-2x-4 ?
The solutions to the equation roots x^2-2x-4 are x=1+sqrt(5),x=1-sqrt(5)
Find the zeros of roots x^2-2x-4
The zeros of roots x^2-2x-4 are x=1+sqrt(5),x=1-sqrt(5)