What are the solutions to the equation x^2+11x+28=70 ?

The solutions to the equation x^2+11x+28=70 are x=3,x=-14

Find the zeros of x^2+11x+28=70

The zeros of x^2+11x+28=70 are x=3,x=-14

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x^{2} + 11 x + 28 = 70

x = 3, x = - 14

Solution steps

x^{2} + 11 x + 28 = 70

Move

70

to the left side

x^{2} + 11 x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot ( - 42 )}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot (- 42) = 17

x_{1, 2} = \frac{- 11 \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 17}{2 \cdot 1}, x_{2} = \frac{- 11 - 17}{2 \cdot 1}

x = \frac{- 11 + 17}{2 \cdot 1} : 3

x = \frac{- 11 - 17}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

x = 3, x = - 14

- x^{2} + 4 x - 7

s^{2} - 3 s - 10 = 0

x^{2} + 4 = - 5 x

x^{2} - 7 x + 10 = 0

h^{2} - 25894.4 h + 1336336 = 0

What are the solutions to the equation x^2+11x+28=70 ?
The solutions to the equation x^2+11x+28=70 are x=3,x=-14
Find the zeros of x^2+11x+28=70
The zeros of x^2+11x+28=70 are x=3,x=-14