What are the solutions to the equation roots x^2+36x+c ?

The solutions to the equation roots x^2+36x+c are x=-18+sqrt(-c+324),x=-sqrt(-c+324)-18

Find the zeros of roots x^2+36x+c

The zeros of roots x^2+36x+c are x=-18+sqrt(-c+324),x=-sqrt(-c+324)-18

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roots

x^{2} + 36 x + c

x = - 18 + - c + 324, x = - - c + 324 - 18

Solution steps

x^{2} + 36 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 36 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

3 6^{2} - 4 \cdot 1 \cdot c : 2 324 - c

x_{1, 2} = \frac{- 36 \pm 2 324 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 36 + 2 324 - c}{2 \cdot 1}, x_{2} = \frac{- 36 - 2 324 - c}{2 \cdot 1}

x = \frac{- 36 + 2 324 - c}{2 \cdot 1} : - 18 + - c + 324

x = \frac{- 36 - 2 324 - c}{2 \cdot 1} : - - c + 324 - 18

The solutions to the quadratic equation are:

x = - 18 + - c + 324, x = - - c + 324 - 18

x^{2} + 49

4 x^{2} + 6 x = 12

x^{2} + 81

a^{2} = 5 a + 104

2 x^{2} - 8 x = - 8

What are the solutions to the equation roots x^2+36x+c ?
The solutions to the equation roots x^2+36x+c are x=-18+sqrt(-c+324),x=-sqrt(-c+324)-18
Find the zeros of roots x^2+36x+c
The zeros of roots x^2+36x+c are x=-18+sqrt(-c+324),x=-sqrt(-c+324)-18