What are the solutions to the equation completesquare 4x^2+6x=12 ?

The solutions to the equation completesquare 4x^2+6x=12 are x=(sqrt(57)-3)/4 ,x=(-sqrt(57)-3)/4

Find the zeros of completesquare 4x^2+6x=12

The zeros of completesquare 4x^2+6x=12 are x=(sqrt(57)-3)/4 ,x=(-sqrt(57)-3)/4

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4 x^{2} + 6 x = 12

x = \frac{57 - 3}{4}, x = \frac{- 57 - 3}{4}

Decimal Notation

x = 1.13745 \dots, x = - 2.63745 \dots

Solution steps

4 x^{2} + 6 x = 12

Divide both sides by

4

\frac{4 x ^{2} + 6 x}{4} = \frac{12}{4}

x^{2} + \frac{3 x}{2} = 3

Rewrite in the form

(x + a)^{2} = b

(x + \frac{3}{4})^{2} = \frac{57}{16}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{3}{4} = \frac{57}{16} : x = \frac{57 - 3}{4}

Solve

x + \frac{3}{4} = - \frac{57}{16} : x = \frac{- 57 - 3}{4}

The solutions to the quadratic equation are:

x = \frac{57 - 3}{4}, x = \frac{- 57 - 3}{4}

x^{2} + 81

a^{2} = 5 a + 104

2 x^{2} - 8 x = - 8

s^{2} + s + 6

3 t^{2} - 16 t + 28 = 0

What are the solutions to the equation completesquare 4x^2+6x=12 ?
The solutions to the equation completesquare 4x^2+6x=12 are x=(sqrt(57)-3)/4 ,x=(-sqrt(57)-3)/4
Find the zeros of completesquare 4x^2+6x=12
The zeros of completesquare 4x^2+6x=12 are x=(sqrt(57)-3)/4 ,x=(-sqrt(57)-3)/4