What are the solutions to the equation 5(5x-6)^2-27=18 ?

The solutions to the equation 5(5x-6)^2-27=18 are x= 9/5 ,x= 3/5

Find the zeros of 5(5x-6)^2-27=18

The zeros of 5(5x-6)^2-27=18 are x= 9/5 ,x= 3/5

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5 (5 x - 6)^{2} - 27 = 18

x = \frac{9}{5}, x = \frac{3}{5}

Decimal Notation

x = 1.8, x = 0.6

Solution steps

5 (5 x - 6)^{2} - 27 = 18

Move

27

to the right side

5 (5 x - 6)^{2} = 45

Divide both sides by

5

(5 x - 6)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 6 = 9 : x = \frac{9}{5}

Solve

5 x - 6 = - 9 : x = \frac{3}{5}

The solutions to the quadratic equation are:

x = \frac{9}{5}, x = \frac{3}{5}

3 x^{2} + 5 x + 1 = 0

a^{2} = - 5 a + 6

(60 - 3 x) \times (32 - x) = 480

- x^{2} = 12

x, x^{2} + y^{2} = c^{2}

What are the solutions to the equation 5(5x-6)^2-27=18 ?
The solutions to the equation 5(5x-6)^2-27=18 are x= 9/5 ,x= 3/5
Find the zeros of 5(5x-6)^2-27=18
The zeros of 5(5x-6)^2-27=18 are x= 9/5 ,x= 3/5