What are the solutions to the equation -x^2=12 ?

The solutions to the equation -x^2=12 are x=2sqrt(3)i,x=-2sqrt(3)i

Find the zeros of -x^2=12

The zeros of -x^2=12 are x=2sqrt(3)i,x=-2sqrt(3)i

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- x^{2} = 12

x = 23 i, x = - 23 i

Solution steps

- x^{2} = 12

Divide both sides by

- 1

x^{2} = - 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 12, x = - - 12

- 12 = 23 i

- - 12 = - 23 i

x = 23 i, x = - 23 i

x, x^{2} + y^{2} = c^{2}

4 a^{2} x^{2} + 8 a x + 3 = 0

2 x^{2} - 11 x + 16 = 0

x, 3 k x^{2} - 5 x = 4 (x - 1)

10 x^{2} - 6 x - 3 = 0

What are the solutions to the equation -x^2=12 ?
The solutions to the equation -x^2=12 are x=2sqrt(3)i,x=-2sqrt(3)i
Find the zeros of -x^2=12
The zeros of -x^2=12 are x=2sqrt(3)i,x=-2sqrt(3)i