What are the solutions to the equation x^2-2(1)-4x=0 ?

The solutions to the equation x^2-2(1)-4x=0 are x=2+sqrt(6),x=2-sqrt(6)

Find the zeros of x^2-2(1)-4x=0

The zeros of x^2-2(1)-4x=0 are x=2+sqrt(6),x=2-sqrt(6)

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x^{2} - 2 (1) - 4 x = 0

x = 2 + 6, x = 2 - 6

Decimal Notation

x = 4.44948 \dots, x = - 0.44948 \dots

Solution steps

x^{2} - 2 (1) - 4 x = 0

Expand

x^{2} - 2 (1) - 4 x : x^{2} - 2 - 4 x

x^{2} - 2 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 2) = 26

x_{1, 2} = \frac{- ( - 4 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 6}{2 \cdot 1} : 2 + 6

x = \frac{- ( - 4 ) - 2 6}{2 \cdot 1} : 2 - 6

The solutions to the quadratic equation are:

x = 2 + 6, x = 2 - 6

- 4 x^{2} - 2 x + 6 = 0

0 = - 0.08 x^{2} + 40 x - 1800

25 (x^{2} - 1) + 12 = - 12

- x - 2 = x^{2} + 4 x + 4

2 x^{2} - 12 x + 3

What are the solutions to the equation x^2-2(1)-4x=0 ?
The solutions to the equation x^2-2(1)-4x=0 are x=2+sqrt(6),x=2-sqrt(6)
Find the zeros of x^2-2(1)-4x=0
The zeros of x^2-2(1)-4x=0 are x=2+sqrt(6),x=2-sqrt(6)