What are the solutions to the equation x^2+128=0 ?

The solutions to the equation x^2+128=0 are x=8sqrt(2)i,x=-8sqrt(2)i

Find the zeros of x^2+128=0

The zeros of x^2+128=0 are x=8sqrt(2)i,x=-8sqrt(2)i

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x^{2} + 128 = 0

x = 82 i, x = - 82 i

Solution steps

x^{2} + 128 = 0

Move

128

to the right side

x^{2} = - 128

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 128, x = - - 128

- 128 = 82 i

- - 128 = - 82 i

x = 82 i, x = - 82 i

(x + 1) (x + 2) = 30

\frac{x ^{2}}{4} + 9 = 0

6 x^{2} + 5 x - 2 = 10 + 2 x^{2} - 3 x

3 c^{2} + 12 c + 11 = 0

2 y^{2} - 6 y + 8 = 0

What are the solutions to the equation x^2+128=0 ?
The solutions to the equation x^2+128=0 are x=8sqrt(2)i,x=-8sqrt(2)i
Find the zeros of x^2+128=0
The zeros of x^2+128=0 are x=8sqrt(2)i,x=-8sqrt(2)i